EMNA Q.11

  • Option : D
  • Explanation : Let HCF be h and LCM be l.
    I.  Let, numbers be ah and bh. Then abh = and (a + b)h = m
    => (a — b)h = n
    Using these ah and bh can be uniquely determined. Thus, I is true II.
    II.  If HCF = LCM, then two numbers are equal and same as HCF or LCM. Thus, II is true.
    III. LCM/HCF = prime i.e. l/h =P Then one of the numbers is equal to h and other is equal to E. Thus, III is true.
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