July 2016 - Paper 3

26:   Given the following statements :

(A) Frequency Division Multiplexing is a technique that can be applied when the
bandwidth of a link is greater than combined bandwidth of signals to be transmitted.

(B) Wavelength Division Multiplexing (WDM) is an analog multiplexing Technique to
combine optical signals.

(C) WDM is a Digital Multiplexing Technique.

(D) TDM is a Digital Multiplexing Technique.

Which of the following is correct ?
A.

(A), (B), (C) and (D) are true.

B.

(A), (B), (C) and (D) are false.

C.

(A), (B) and (D) are false; (C) is true.

D.

(A), (B) and (D) are True; (C) is false.

 
 

Option: D

Explanation :

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27:  

A pure ALOHA Network transmits 200 bit frames using a shared channel with 200 Kbps bandwidth. If the system (all stations put together) produces 500 frames per second, then the throughput of the system is ______.

A.

0.384

B.

0.184

C.

0.286

D.

0.586

 
 

Option: B

Explanation :

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28:  
Match the following :
 
(a) Line coding                              (i) A technique to change analog signal to digital data.
 
(b) Block coding                           (ii) Provides synchronization without increasing number of bits.
 
(c) Scrambling                             (iii) Process of converting digital data to digital signal.
 
(d) Pulse code modulation           (iv) Provides redundancy to ensure synchronization and inherits error detection.
A.

(iv) (iii) (ii) (i)

B.

(iii) (iv) (ii) (i)

C.

(i) (iii) (ii) (iv)

D.

(ii) (i) (iv) (iii)

 
 

Option: B

Explanation :

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29:  

Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is _____.

A.

1.636 Kbps

B.

1.636 Mbps

C.

3.272 Mbps

D.

3.272 Kbps

 
 

Option: B

Explanation :

Bit rate = 100*24*80*8 = 1.636 Mbps

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30:  

Encrypt the plain text Message “EXTRANET” using Transposition cipher technique with the following key : Using ‘Z’ as bogus character.


21252
A.

TAXERTZENZ

B.

EXTRANETZZ

C.

EZXZTRZANZET

D.

EXTZRANZETZ

 
 

Option: A

Explanation :

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