CP I/O Q9
0. The following program fragment unsigned i = 1; int j = -4; printf ("%u ", i + j); prints
- Option : C
- Explanation : In the computer I used to execute this program. The output was 4294967293. That's because in my system, sizeof (int ) is 4 bytes (32 bits), and negative numbers are represented in 2's complement form. This means -4 will be represented as 11111111 11111111 11111111 11111100 (i.e. 30 one's followed by 2 zeroes). Note that this number is 232 - 1 - 3. Before j gets added to 1, it will be converted to an unsigned integer. So, i + j is essentially adding 1 to 232- 1 - 3 which gives 4294967293.
