The root of x3 - 2x - 5 = 0 correct to three decimal places by using Newton-Raphson method is
A. | 2.0946 |
B. | 1.0404 |
C. | 1.7321 |
D. | 0.7011 |
Option: A Explanation : Click on Discuss to view users comments. |
Newton-Raphson method of solution of numerical equation is not preferred when
A. | Graph of A(B) is vertical |
B. | Graph of x(y) is not parallel |
C. | The graph of f(x) is nearly horizontal-where it crosses the x-axis. |
D. | None of these |
Option: C Explanation : Click on Discuss to view users comments. |
Following are the values of a function y(x) : y(-1) = 5, y(0), y(1) = 8
dy/dx at x = 0 as per Newton's central difference scheme is
A. | 0 |
B. | 1.5 |
C. | 2.0 |
D. | 3.0 |
Option: B Explanation : Click on Discuss to view users comments. |
A root of the equation x3 - x - 11 = 0 correct to four decimals using bisection method is
A. | 2.3737 |
B. | 2.3838 |
C. | 2.3736 |
D. | None of these |
Option: C Explanation : Click on Discuss to view users comments. |
Newton-Raphson method is applicable to the solution of
A. | Both algebraic and transcendental Equations |
B. | Both algebraic and transcendental and also used when the roots are complex |
C. | Algebraic equations only |
D. | Transcendental equations only |
Option: A Explanation : Click on Discuss to view users comments. |