Linear Algebra - Linear Algebra

51:  

The solution of the given matrix equation is

A.

x1=0, x2=0, x3=0

B.

x1=1, x2=1, x3=0

C.

x1=0, x2=1, x3=1

D.

x1=2, x2=-5, x3=-1

 
 

Option: A

Explanation :

Let matrices 

 AX = B

Multiplying both sides by A-1

X = A-1B

But as B = 0 therfore X = 0

Hence 

  x1 = 0, x2 = 0, x3 = 0

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52:  

If product of matrix

is a null matrix, then θ and Φ differ by an

A.

odd multiple of π

B.

even multiple of π

C.

odd multiple of π/2

D.

even multiple of π/2

 
 

Option: C

Explanation :

A null matrix, when cos 

i.e. if   

is an odd miltiple of 

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53:  

Sum of the eigen values of the matrix 

for real and negative values of x is

A.

greater than zero

B.

less than zero

C.

zero

D.

dependent on value of x

 
 

Option: A

Explanation :

Eigen values are given by the solution of equation

Since x is real and negative, put x = -k, where k is positive constant

If λand λ2 be the solutions of the above equations then λand λare eigen values.

Now sum of eigen values = sum of roots of the above equation

= 4 (> 0 )

 

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54:  

The system of equations 

4x + 6y = 8

7x + 8y = 9

3x + 2y = 1

has

A.

no solutions

B.

only one solution

C.

two solutions

D.

infinite number of solutions

 
 

Option: B

Explanation :

For given system of equations

= 4 (8 - 18) - 6 (7 - 27) + 8 (14 - 24)

= -40 + 120 - 80 = 0

Since  = 0, hence given system of equations has unique solution, i.e. only one solution.

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55:  

The system of equations 

4x + 6y = 8

7x + 8y = 9

3x + 2y = 1

has

A.

no solutions

B.

only one solution

C.

two solutions

D.

infinite number of solutions

 
 

Option: B

Explanation :

For given system of equations

= 4 (8 - 18) - 6 (7 - 27) + 8 (14 - 24)

= -40 + 120 - 80 = 0

Since  = 0, hence given system of equations has unique solution, i.e. only one solution.

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