Numbers & Algebra - Numbers and Algebra MCQ

41:  

Average marks of 15 students in a class is 145, maximum marks being 150. If two lowest scores are removed, the average increases by 5. Also, two lowest scores are consecutive multiples of 9. What is lowest score in the.class?

A.

126

B.

117

C.

108

D.

None of these

 
 

Option: C

Explanation :

Total marks of 15 students = 15 x 145 = 2175.
Average marks of 15 students (excluding two lowest scores) = 13 x (145 + 5) = 1950.
∴ Total of two lowest scores = 2175 1950 = 225
Given that two scores are consecutive multiples of 9 * 9x + 9x + 9 = 225 18x = 216
=> 18/x = 216 => x = 216/18
Lowest score = 9x = (216/18) x 9 = 108

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42:  

revise 39. What is the sum upto 20 terms of the series?
2 8 26 80
- + - + -- + -- + ....?
3 9 27 81

A.

(19.3²⁰+1) / 3²⁰

B.

(19.3²⁰ + 1)/ 2.3²⁰

C.

(19.3²⁰-1)2.3²⁰

D.

(39.3²⁰+1)+2.3²⁰

 
 

Option: D

Explanation :

2 8 26 80 - + - + -- + -- + up to 20 terms 3 9 27 81 =(1-1/3)+(1-1/9)+(1-1/9)+(1-1/27) +(1-1/81)+...up to 20 terms =20-(1/3+1/3²+1/3³+1/3⁴+...+1/3²⁰) =20-1/3((1-(1/3)²⁰) / 1-1/3) =20-(3²⁰-1)/2.3²⁰ =(40.3²⁰-3²⁰+1)/2.3²⁰ =(39.3²⁰+1) / 2.3²⁰

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43:  

revise 48. Three people A, B and C weigh themselves in a particular order. First A, B, C weigh themselves individually and then AB, BC CA and ABC together respectively. Recorded weight for the
last measured is 180 kgs. Then average of the 7 measures is

A.

320 kgs

B.

360/7 kgs

C.

720/7 kgs

D.

Cannot be determined

 
 

Option: C

Explanation :

Order of measures is A,B,C,A+B,B+C,C+A,A+B+C. Given: A + B + C = 180 Hence, average of the 7 measures [[(A)+(B)+(C)+(A+B)(B+C)+(C+A)+(A+B+C)]] =--------------------------------------- 7 = 4/7 (A+B+C) = 4/7 x 180 = 220/7 kgs

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44:  

A gardener had a number of shrubs to plant in horizontal rows. At first he tried to plant 5 shrubs in each row, then 6, then 8 and then 12, but had always 1 left. On trying 13, in one row he had none left. What is the smallest number of shrubs that he could have had?

A.

481

B.

477

C.

468

D.

121

 
 

Option: A

Explanation :

Number is 120K + 1= ((13 * 9 + 3) K + 1) 
= 13 * 9K + 3 K + 1, which is divisible by 13.
3K + 1 is divisible by 13.
 ∴  K = 4. Number = 481

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45:  

Average age of a team of 15 employees is 36. Youngest of them is 20 years old and eldest is 56 years old. Two of them with average age 28 leave the team. If one of the two comes back on the condition that he will be made the team leader, then which of the following can possibly be average age of the new team so formed?

A.

35

B.

36

C.

38

D.

39

 
 

Option: B

Explanation :

Total age = 15 x 36
After two left, total age = 15 x 36 - 2 x 28 = 540 - 56 = 484 years.
Let the age of the person who returns be x years.
Then new average = (484 +x) / 14
Now x lies between 20 and 36 (both inclusive)
New average min = (484 + 20) /14 = 36 years
And New average max = (484 +36)/14 = 520/14 = 37.14. years

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