# Numbers & Algebra - Numbers and Algebra MCQ

26:

What is the least number which must be subtracted from 1936 so that the remainder when divided by 9, 10, 15 will leave in each case the same remainder 7?

 A. 32 B. 53 C. 46 D. 39 Answer Report Discuss Option: D Explanation : L.C.M. of 9, 10 and 15 = 90 ∴ 1936 = 90 x 21 + 46 (Remainder). But a part of this remainder is 7. 39 should be subtracted from 1936. Click on Discuss to view users comments. nidhi said: (2:20pm on Wednesday 19th August 2015) from where 9x21 46 comeshow 39 is the right answer sudeep said: (3:53pm on Monday 28th November 2016) L.C.M of 9,10,15=901936÷90=21. and remainder 46.but remainder is always 7,so 46-7=39. Write your comments here:
27:

What is the maximum sum of the series 60, 58, 56, 54, 52, ?

 A. 840 B. 880 C. 930 D. 1120 Answer Report Discuss Option: C Explanation : Since d = -2, maximum sum of the series will be sum of all the positive terms. Least positive term of the series is 2 or 0 (both giving equal sum) Let, 2 be the nth term 2 = 60 + (n 1) - 2  => n = 30 Required sum = 30/2 (60 + 2) = 930 Click on Discuss to view users comments. Write your comments here:
28:

What is the least number which on being divided by 12, 21 and 35 will leave in each case the same remainder 6?

 A. 210 B. 414 C. 420 D. 426 Answer Report Discuss Option: D Explanation : L.C.M. of 12, 21 and 35 = 420  ∴ Number required = 420 + 6 = 426 Click on Discuss to view users comments. Write your comments here:
29:

Six men A, B, C, D, E, F agree with a seventh man G to provide a sum of money among them. A, B, C, D, E, F are to subscribe Rs.10 each, and G is to pay Rs.3 more than the average of the seven. What is the whole sum to be provided?

 A. Rs.73.50 B. Rs. 74 C. Rs. 73 D. Rs. 72.50 Answer Report Discuss Option: A Explanation : let average of the seven men be x ∴ x = (10x6+(x+3)) / 7 => 60 + x +3 = 7x => x = 63/6 = 10.5 Toal amount = 10.5 x 7 = 73.5 Click on Discuss to view users comments. Write your comments here:
30:

What is the greatest number consisting of six digits which on being divided by 6, 7, 8, 9, 10 leaves 4, 5, 6, 7, 8 as remainders respectively?

 A. 997920 B. 997918 C. 999999 D. 997922 Answer Report Discuss Option: B Explanation : 6 - 4 = 2, 7 - 5 = 2,  8 - 6 = 2,  9 - 7 = 2,  10 -8 = 2 L.C.M. of 6, 7, 8, 9, 10 = 2520; Greatest number of 6 digits = 999999 2520 x 396 + 2079 = 999999 Remainder = 2079. Subtract 2079 from 999999, then we get 999999- 2079 = 997920. Subtract 2 from this number to get required number, which is 997918 and which will give the remainders 4, 5, 6, 7, 8 when divided by 5, 6, 7, 8, 9 respectively. Click on Discuss to view users comments. Write your comments here: