The number of cross-points needed for 10 lines in a cross-point switch which is full duplex in nature and there are no self connection, is
A. | 100 |
B. | 45 |
C. | 50 |
D. | 90 |
Option: B Explanation : The number of cross points required for n lines in cross point switch which is full duplex in nature is n*(n-1) / 2 for 10 lines it is (10 * 9)/2 = 45 cross points. Click on Discuss to view users comments. |
A group of 2m - 1 routers are interconnected in a centralized binary tree. With router at each tree node. Router I communicates with router J by sending a message to the root of the tree. If root then sends the message back down J, the mean path length will be
A. | 2 (m - 2) |
B. | 2 (2m - 1) |
C. | m - 1 |
D. | (2m - 1)/mJ |
Option: A Explanation : Click on Discuss to view users comments. |
A circuit switching network has the following characteristics :
Set up time = 5 sec
Propagation = 5 sec
Message size = 1 M bits
Data transmission rate = 1 M bits
Data transmission rate = 1
Kbps Number of hops = 10
When will the last bit of the message reach the receiver ?
A. | t = 520 sec |
B. | t = 1000 ms |
C. | t = 250 sec |
D. | t = 1025 sec |
Option: D Explanation : Click on Discuss to view users comments. Ankit said: (11:57am on Sunday 19th May 2013)
what is the formula of calculation??
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Two networks each provide reliable connection-oriented service. One of them offers a reliable byte stream and the other offers a reliable message stream. A process writes 1024 bytes, then
A. | both networks will receive 2048 bytes as a single unit |
B. | message stream network will receive 1024 bytes only at one time. But byte stream network will receive 2048 bytes as a single unit. |
C. | message stream network receives 2048 bytes as a whole. But bytes stream 1024 bytes only at a time. |
D. | both will receive 1024 bytes at one time since there is a gap between writes |
Option: B Explanation : Click on Discuss to view users comments. |
A packet switching network (highly loaded) has the following characteristics:
Propagation delay = 2 sec/hp.
Data transmission rate = 1.
Packet size = r bit = 512 bits.
Number of of hops = 10.
At what time the last bit of the last packet will reach the receiver ?
A. | 1024.5 sec |
B. | 1038 sec |
C. | 2048 sec |
D. | 512 sec |
Option: A Explanation : Click on Discuss to view users comments. Ankit said: (11:58am on Sunday 19th May 2013)
Formula??
rajat said: (2:22pm on Friday 25th August 2017)
How is this solved explain please??
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