A. |
resolution
|
B. |
floating point precision of the system
|
C. | associated software |
D. | All of these |
Option: D Explanation : Click on Discuss to view users comments. |
A. |
f(x) = x2- | x |
|
B. |
f(x) = sin (x) + cos (x)
|
C. | f(x) = (x) (ax + 1) / (ax- 1) |
D. | none of the above |
Option: D Explanation :
f(x) = x2 - I x l and f(x) =(x) (ax + 1) / (ax -1) are even functions, because
f(x) = f(-x) . f(x) = sin (x) + cos (x) is neither even nor odd as f(x) ≠ f (-x) and - f(x) ≠ f (-x) Click on Discuss to view users comments. |
A. |
reversing the order of bits within each row in the frame buffer
|
B. |
by performing XOR on the frame buffer location
|
C. |
by copying each row of the block into a column in the new frame buffer location
|
D. | none of the above |
Option: C Explanation : Click on Discuss to view users comments. |
A. |
codes of the end points are the same.
|
B. |
logical AND of the end points code is not 0000.
|
C. |
logical OR of the end points code is 0000.
|
D. | Both (a) & (b) |
Option: D Explanation : Click on Discuss to view users comments. suni nair said: (6:17pm on Saturday 23rd November 2013)
sir..i think all options are correct.a) if the code of both enpoints are same then lne is in any one region.ie. either completely outside or completely inside.b)this is the condition when a line is trivially rejectedc) this is the condition when a line is trivially accepted.so here no need of clipping
|
A. |
f (x) = x - [ x ]; where [ x ] stands for the greatest integer ≤ x
|
B. |
f(x) = | cos (x) |
|
C. | Both (a) & (b) |
D. | f(x) = sin ( 1 / x ) , if x ≠ 0 ; 0 otherwise |
Option: C Explanation :
For f ( x ) = x - [ x ]; where [ x ] stands for the greatest integer ≤ x,
solving the equation f ( x + T ) = f (x), we get T= 1 as the period. f(x) = |cos (x) | is periodic with period π n.f(x) = (x) cos (x) and
f(x) = sin ( 1 / x )
if x ≠ 0; 0 otherwise are not periodic. Click on Discuss to view users comments. |
Syllabus Covered in this section is -
This Section covers Multiple Choice Questions Answers in Computer Graphics .
Who can benefit -
Various Search Terms used for this section are