December 2015 - Paper 2

21:  

Which of the following services is not provided by wireless access point in 802.11 WLAN?

A.

Association

B.

Disassociation

C.

Error Correction

D.

Integration

 
 

Option: C

Explanation :

IEEE 802.11 services

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22:   Which of the following fields in IPv4 datagram is not related to fragmentation?
A.

Type of service

B.

Fragment offset

C.

Flags

D.

Identification

 
 

Option: A

Explanation :

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23:  

Four channels are multiplexed using TDM. If each channel sends 100 bytes/second and we multiplex 1 byte per channel, then the bit rate for the link is ...............

A.

400 bps

B.

800 bps

C.

1600 bps

D.

3200 bps

 
 

Option: D

Explanation :

The multiplexer is shown in the Figure.

computer science december 2015 paper

Each frame carries 1 byte from each channel; the size of each frame, therefore, is 4bytes, or 32 bits. Because each channel is sending 100 bytes/s and a frame carries 1 byte from each channel, the frame rate must be 100 frames per second. The bit rate is 100 × 32 = 3200 bps.

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24:  
In a typical mobile phone system with hexagonal cells, it is forbidden to reuse a frequency band in adjacent cells. If 840 frequencies are available, how many can be used in a given cell?
A.

280

B.

210

C.

140

D.

120

 
 

Option: A

Explanation :

Each cell has six other adjacent cells, in a hexagonal grid. If the central cell uses frequency group A, its six adjacent cells can use B, C, B, C, B, and C respectively. In other words, only 3 unique cells are needed. So the answer is 840/3 = 280 frequencies.
december 2015 computer science solved paper

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25:  

Using p=3, q=13, d=7 and e=3 in the RSA algorithm, what is the value of ciphertext for a plain text 5?

A.

13

B.

21

C.

26

D.

33

 
 

Option: D

Explanation :

p=3, q=13, d=7, e=3, M=5, C=?
 
C = M e  mod n
 
n = p*q
 
 = 3*13 = 39
 
C = 5 3  mod 39
 
 = 8

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