There are (n + 1) white and (n + 1) black balls each set numbered 1 to n + 1. The number of ways in which the balls can be arranged in a row so that adjacent balls are of different colours, is
| A. | (2n + 2)! |
| B. | (2n + 2)! X 2 |
| C. | (n + I)! x 2 |
| D. | 2 {(n + 1)!}2 |
Answer : D Explanation : |
|
|
Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. |
