The root of x3  2x  5 = 0 correct to three decimal places by using NewtonRaphson method is
A.  2.0946 
B.  1.0404 
C.  1.7321 
D.  0.7011 
Option: A Explanation : Click on Discuss to view users comments. 
NewtonRaphson method of solution of numerical equation is not preferred when
A.  Graph of A(B) is vertical 
B.  Graph of x(y) is not parallel 
C.  The graph of f(x) is nearly horizontalwhere it crosses the xaxis. 
D.  None of these 
Option: C Explanation : Click on Discuss to view users comments. 
Following are the values of a function y(x) : y(1) = 5, y(0), y(1) = 8
dy/dx at x = 0 as per Newton's central difference scheme is
A.  0 
B.  1.5 
C.  2.0 
D.  3.0 
Option: B Explanation : Click on Discuss to view users comments. Piyali said: (8:12pm on Monday 29th July 2013)
please explain the ans

A root of the equation x3  x  11 = 0 correct to four decimals using bisection method is
A.  2.3737 
B.  2.3838 
C.  2.3736 
D.  None of these 
Option: C Explanation : Click on Discuss to view users comments. 
NewtonRaphson method is applicable to the solution of
A.  Both algebraic and transcendental Equations 
B.  Both algebraic and transcendental and also used when the roots are complex 
C.  Algebraic equations only 
D.  Transcendental equations only 
Option: A Explanation : Click on Discuss to view users comments. 