Linear Algebra

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Linear Algebra - Linear Algebra

21:

Determinant of the matrix

A.	100
B.	200
C.	1
D.	0
	Answer Report Discuss
	Option: C Explanation : Click on Discuss to view users comments. priyanka said: (11:00pm on Wednesday 1st July 2015) the given matrix is referred as lower triangular matrix . then the determinant of that type of matrix is the product of diagonal elementsfrom the above given matrix, the diagonal elements are 1,1,1,1the product of 1.1.1.1=1 Write your comments here: Updating your Comments.. Updating your Comments..

22:

The

vector

-1

eigen

vector

one of the eigen values of A is

A.	1
B.	2
C.	5
D.	-1
	Answer Report Discuss
	Option: C Explanation : Click on Discuss to view users comments. Write your comments here: Updating your Comments.. Updating your Comments..

23:

Given : A =

Sum of the eigen values of the matrix A is

A.	10
B.	-10
C.	24
D.	22
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	Option: A Explanation : Click on Discuss to view users comments. Write your comments here: Updating your Comments.. Updating your Comments..

24:

Given: Matrix A =

the Largest eigen value is

Answer Report Discuss

Option: D

Explanation :

Now

⇒

⇒

3-λ

⇒

3-λ

Hence eigen values are 0,0,3

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25:

Corresponding to highest eigen value the eigenvector is

A.	$\begin{bmatrix} 0\\1\\2 \end{bmatrix}$
B.	$\begin{bmatrix} 1\\2\\0 \end{bmatrix}$
C.	$\begin{bmatrix} 2\\1\\0 \end{bmatrix}$
D.	$\begin{bmatrix} 2\\0\\1 \end{bmatrix}$
	Answer Report Discuss
	Option: C Explanation : Repeating above procedure, we get successively $4\begin{bmatrix} 2.1\\1.1\\0 \end{bmatrix};4\begin{bmatrix} 2.1\\1.1\\0 \end{bmatrix};4.4\begin{bmatrix} 2\\1\\0 \end{bmatrix};4\begin{bmatrix} 2\\1\\0 \end{bmatrix};4\begin{bmatrix} 2\\1\\0 \end{bmatrix}.$ It follows that the largest eignevalue is 4 and corresponding eigenvector is $\begin{bmatrix} 2\\1\\0 \end{bmatrix}.$ Click on Discuss to view users comments. Write your comments here: Updating your Comments.. Updating your Comments..

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