If AT = A1, where A is a real matrix, then A is
A.  normal 
B.  symmetric 
C.  Hermitian 
D.  orthogonal 
Option: D Explanation : Click on Discuss to view users comments. 
If A and B are nonzero square matrices, then AB = 0 implies
A.  A and B are orthogonal 
B.  A and B are singular 
C.  B is singular 
D.  A is singular 
Option: A Explanation : Click on Discuss to view users comments. MABUD ALI SARKAR said: (10:39pm on Thursday 10th December 2015)
SINCE PRODUCT OF TWO NONZERO VECTORS IMPLIES THEY ARE ORTHOGONAL TO EACH OTHER. SO A and B ARE ORTHOGONAL

If A and B be real symmetric matrices of sizen n x n, then
A.  AA^{T} = 1 
B.  A = A^{1} 
C.  AB = BA 
D.  (AB)^{T} = BA 
Option: D Explanation : Click on Discuss to view users comments. MABUD ALI SARKAR said: (10:42pm on Thursday 10th December 2015)
(AB)^T=(B^T)(A^T) =BA
Zakir ali said: (6:30am on Monday 1st May 2017)
Please tell me about different type of matrices with example

If, A, B, C are square matrices of the same order, then (ABC)1 is equal to
A.  C^{1}A^{1}B^{1} 
B.  C^{1} B^{1} A^{1} 
C.  A^{1} B^{1}C^{1} 
D.  A^{1} C^{1} B^{1} 
Option: B Explanation : Click on Discuss to view users comments. 
Consider the following statements
S1: Sum of the two singular n x n matrices may be nonsingular
S2 : Sum of two the nonsingular nx n matrices may be singular.
Which of the following statements is correct?
A.  S1 and S2 are both true 
B.  S1 is true, S2 is false 
C.  S1 is false, S2 is true 
D.  S1 and S2 are both false 
Option: A Explanation : Click on Discuss to view users comments. kabil said: (12:11am on Monday 2nd September 2013)
i thing option b may be correct because two singular matrix satisfy.but two non singular matrix doesn't satisfy. sorry if i did wrong
