In how many ways can 5 prizes be distributed among 4 boys when every boy can take one or more prizes ?
| A. | 1024 |
| B. | 625 |
| C. | 120 |
| D. | 600 |
Answer : A Explanation : Required number of ways are 45=1024. Since each prize can be distributed in 4 ways Jeevan Gyawali said: (2:24am on Wednesday 16th August 2017)
I don't think the answer is correct in this context. For A to make sense, there needs to be an unlimited supply of the 5 TYPES of prizes. If there are only 5 prizes, the only possible options are :2,1,1,1 -> 4C1 =42,2,1,0 -> 4C2 * 2C1 = 243,1,1,0 -> 4C1 * 3C2 = 123,2,0,0 -> 4C1 * 3C1 = 124,1,0,0 -> 4C1 = 45,0,0,0 -> 4C1 = 4 So, total = 4 24 12 12 12 4 = 68
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Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. |
