Calculus

1:

The function f(x) = x3 - 6x2 + 9x + 25 has

A.

a maxima at x= 1 and a minima at x = 3

B.

a maxima at x = 3 and a minima at x = 1

C.

no maxima, but a minima at x = 1

D.

a maxima at x = 1, but no minima

 

Answer : A

Explanation :

f '(x) = 3(x2-4x+3)    f ''(x)=6(x)-12
at  x=1,  f "(1)  
at  x=3, f ''(3) = +ve

abc said: (9:22am on Friday 5th April 2013)
how x=1 and x=3 arrive??
Akem said: (1:02pm on Tuesday 8th September 2015)
i taught maxima at x=3 because is positive and minima at x = 1 because it is negative
Jay Vyas said: (4:14pm on Friday 27th November 2015)
at X = 1 We got minimum value and at X= 3 we got maximum valueSo in my opinion option B is right
Samrah said: (2:38am on Wednesday 13th July 2016)
Take 1st derivative of the function and put it equal to 0 to find the value of "x".Now take 2nd derivative and put the 2 values of X previously found in equation to get a result respectively. If the final answer is ve so it is a Minima. If the answer is -ve it is a maxima.

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Option: A

Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here.