Calculus

1:

The maxima and minima of the function
f(x) = 2x3 - 15x2 + 36x + 10 occur respectively at

A.

x= 3 and x = 2

B.

x = 1 and x = 3

C.

x = 2 and x = 3

D.

x = 3 and x = 4

 

Answer : C

Explanation :

f(x)=2x3-15x2+36x+10
f '(x)=6x2-30x+36 and f ''(x)=12x-30
For maxima and minima,
f '(x)=0 
6x2-30x+36 = 0 or
x2- 5x + 6 = 0 or 
X = 3,2

Putting these values of x in equation (ii), we get
f '(3) = 36 - 30 = + 6 positive
Hence minimum value = 3
f ' (2) = 24 - 30 = - 6 negative, hence maximum value = 2

Write your comments here:


Report Error
 

Option: A

Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here.