Calculus

Minimum point of the function

$\small \fn_cm f(x)=\frac{x^{3}}{x}$
is at

A.	x=1
B.	x=-1
C.	x=0
D.	x= 1/√3
	Answer : A Explanation : $\small \fn_cm f(x)=\frac{x^{3}}{x}$ => f'(x)= x²-1 For maximum and minimum value, f'(x) = 0 ∴ x² -1= 0 x = ± 1 Again f(x) = 2x At x = 1, f '(x) = 2 > 0 f '(x) = -2 < 0 Hence minimum at x = 1 ishan said: (1:51am on Friday 30th September 2016) how derivative of fx =x2 -1 while fx= x3/x=x2 Write your comments here: Updating your Comments.. Updating your Comments.. Report Error
	Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here.

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