Numbers & Algebra

1:

What is the least number which on being divided by 5, 6, 8, 9, 12 leaves in each case a remainder 1 but when divided by 13 leaves no remainder?

A.

2987

B.

3601

C.

3600

D.

2986

 

Answer : B

Explanation :

L.C.M. of 5, 6, 8, 9 and 12 is 360
Required number = 360 K + 1 = (13 x 27 + 9) K + 1
= (13 x 27) K + (9K + 1)
Now this number must be divisible by 13 K = 10 and required number = 3601.

Write your comments here:


Report Error
 

Option: A

Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here.