Numbers & Algebra

1:

What is the least number which must be subtracted from 1936 so that the remainder when divided by 9, 10, 15 will leave in each case the same remainder 7?

A.

32

B.

53

C.

46

D.

39

 

Answer : D

Explanation :

L.C.M. of 9, 10 and 15 = 90
∴ 1936 = 90 x 21 + 46 (Remainder).
But a part of this remainder is 7.
39 should be subtracted from 1936.

nidhi said: (2:20pm on Wednesday 19th August 2015)
from where 9x21 46 comeshow 39 is the right answer
sudeep said: (3:53pm on Monday 28th November 2016)
L.C.M of 9,10,15=901936÷90=21. and remainder 46.but remainder is always 7,so 46-7=39.

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Option: A

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