HCF of y3 - 4y and 4y (y3 + 8) is
A. | y(y + 2) |
B. | y - 2 |
C. | 2 (y + 2) |
D. | (y + 2)(y2- 2y + 4) |
Answer : A Explanation :
y3-4y = y(y2-4) |
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