In tuple relational calculus P1 → P2 is equivalent to
| A. | ¬ P1 ∨ P2 |
| B. | P1 ∨ P2 |
| C. | P1 ∧ P2 |
| D. | P1 ∧ ¬P2 |
Answer : A Explanation : |
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Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. |
