C Programming MCQ

1: If the following program fragment(assume negative numbers are stored in 2's complement form) unsigned i=1; int j=-4; printf("%d",8*size of(int)); output is (log in answers are to the base two)

A.	An unpredictable value
B.	8*log(x+3)
C.	log(x+3)
D.	None of these
	Answer : C Explanation : Let size of (int)=1. So, -4 will be stored as 11111100. Since we are adding unsigned and signed integers the signed gets converted to unsigned. So, i + j will become 11111101. We are trying to print this as an unsigned integer. So, what is printed will be 2⁸-1-2. So, log (x+3)=8(i.e,size of (int)). barbee doll said:* (12:10pm on Tuesday 8th August 2017) Please explain it that how -4 will be stored in 11111100 form while 4 binary form is that 00000101 Write your comments here: Updating your Comments.. Updating your Comments.. Report Error
	Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here.

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C Programming MCQ

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