The library function sqrt operates on a double precision argument. If, i is an integer variable, then which of the following calls would correctly compute sqrt(i)?
| A. | sqrt((double)i) |
| B. | (double)sqrt(i)? |
| C. | (double)(sqrt(i)) |
| D. | sqrt(i) |
Answer : A Explanation : |
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Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. |
