puts(argv[0]);
| A. | prints the name of the source code file |
| B. | prints argv |
| C. | prints the number of command line arguments |
| D. | prints the name of executable code file |
Answer : D Explanation : arg [0] is a pointer to the executable code file name. So, puts (argv [0]) ; prints it. |
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Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. |
