The following statement
prlntf( ‘%f ’, 9/5) ;
prints
| A. | 1.8 |
| B. | 1.0 |
| C. | 2.0 |
| D. | 0.00 |
Answer : D Explanation : This statement is undefined behavior because the argument has to be of type double and 9 / 5 is of type int. Following program yields an output of 1.8
int main()
{
printf("%f",9/5.0);
return 0;
}
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Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. |
