Consider a logical address space of 8 pages of 1024 words mapped into memory of 32 frames.
How many bits are there in the physical address?
A. | 9 bits |
B. | 11 bits |
C. | 13 bits |
D. | 15 bits |
Answer : D Explanation : For (25), 1132 frames of 1024 words each (page size= frame size) we have 5 + 10 = 15 bits. |
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Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. |