In a paged memory, the page hit ratio is 0.35. The time required to access a page in secondary memory is equal to 100 ns. The time required to access a page in primary memory is 10 ns. The average time required to access a page is
| A. | 3.0 ns |
| B. | 68.0 ns |
| C. | 68.5 ns |
| D. | 78.5 ns |
Answer : C Explanation : 0.35 x 10 + (1 - 0.35) x 100 = 68.5 ns Shivani said: (10:16pm on Saturday 2nd June 2018)
Why not 0.35x10 (1-0.35)x(10 100) as it will first search in main memory?
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Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. |
