int a =1 , b=2;
a=chg(b) ;
cout << a << b ;
If the function chg is coded as
int chg(const int &x)
{
x=10;
return ()
};
then Functions
| A. | it results in compile-time error |
| B. | it results in run time error |
| C. | it prints 112 |
| D. | it prints 111 0 |
Answer : A Explanation : Here the function chg tries to change the parameter x, which is not allowed as it is declared to be a constant integer. So, the compiler gives an error. |
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Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. |
