If integer needs two bytes of storage, then maximum value of a signed integer is
| A. | 216 -1 |
| B. | 215 -1 |
| C. | 216 |
| D. | 215 |
|
Option: B Explanation : In signed magnitude form, one bit is dedicated to store the sign. (e.g.. 1 for negative and 0. otherwise). Only the remaining 15 bits arc available to store the magnitude. Hence the answer. Click on Discuss to view users comments. |
printf ( "%d" , printf ( "tim" ) ):
| A. | results in a syntax error |
| B. | outputs tim3 |
| C. | outputs garbage |
| D. | prints tim and terminates abruptly |
|
Option: B Explanation : Any function (including main ( ) ) , returns a value to the calling environment. In the case of printf , it is the number of characters it printed. So. the output will be tim3 (since it printed the three characters a, b, c). Click on Discuss to view users comments. |
If abc is the input, then the following program fragment
char x, y, z ;
printf ("% d" , scanf ("%c%c%c" , &x , &y , &z )) ;
results in
| A. | a syntax error |
| B. | a fatal error |
| C. | segmentation violation |
| D. | printing of 3 |
|
Option: D Explanation :
take refrence from below. Click on Discuss to view users comments. HIFZURRAHAMAN said: (12:08am on Tuesday 27th December 2016)
after running the program the output is obtained: -1
|
Consider the statements
putchar ( getchar ( ));
putchar(getchar( ));
if
a
b
is the input, the output will be
| A. | an error message |
| B. | this can't be the input |
| C. | ab |
| D. | a b |
|
Option: B Explanation : The input is actually a \ n b. Since we are reading only two charactcrs, only a and \ will be read and printed. Click on Discuss to view users comments. |
