The following program fragment
int k = -7;
printf(“%d", 0 < lk);
| A. | prints 0 |
| B. | prints a non-zero value |
| C. | is illegal |
| D. | prints an unpredictable value |
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Option: A Explanation : k = -7. So, if 'k' is used as a Boolean variable, it will be treated as a true condition. So. ! k will be false i.e., 0. So, 0 < ? !k is actually 0 < 0. which is false. So. 0 will be printed. Click on Discuss to view users comments. |
The following program fragment
int a = 4, b = 6;
printf (" %d ", a == b);
| A. | outputs an error message |
| B. | prints 0 |
| C. | prints 1 |
| D. | none of the above |
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Option: B Explanation : Click on Discuss to view users comments. |
The following program fragment
int a = 4, b = 6;
printf (" %d ", a != b) ;
| A. | outputs an error message |
| B. | prints 0 |
| C. | prints 1 |
| D. | none of these |
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Option: C Explanation : Click on Discuss to view users comments. |
The following program fragment
int a = 4, b = 6;
printf ("%d", a = b) ;
| A. | outputs an error message |
| B. | prints 0 |
| C. | prints 1 |
| D. | 6 |
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Option: D Explanation : Here in this program, the output will be '6' . The program assigns b's value to a. So, a becomes 6. While, the "%d" will display value of the second variable in the printf statement which is "b=6" Click on Discuss to view users comments. suman sharma said: (4:23pm on Wednesday 18th September 2013)
output of this program is=6;because we assign the value of b to a, we have b=6 then automatically value a=6;
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The following program fragment
int i = 107, x = 5;
printf (( x > 7) ? " %d " : "%c", i ) ;
results in
| A. | an execution error |
| B. | a syntax error |
| C. | printing of k |
| D. | none of the above |
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Option: C Explanation : Since x > 7 is false, the ternary operator?: returns "%c". So, print f ( "%c " , i) will be executed. So, the ASCII character corresponding to 107, i.e., ' k ' will be printed. Click on Discuss to view users comments. |
