Classical

Computer Networks - Data Communication & Network Security

31:  

It is desired to send a sequence of computer screen images over an optical fiber. The screen is 480 x 640 pixels, each pixel being 24 bits. There are 60 screen images per second. How much bandwidth is needed, and how many microns of wavelenth are needed for this band at 1.30 microns?

A.

1.0 x 105 microns

B.

2 x 105 microns

C.

2.5 x 105 microns

D.

5 x 105 microns

 
 

Option: C

Explanation :

Data rate is 480 x 640 x 24 x 60 bps, which is 442 Mbps.
Assume 1 bps per Hz. ∆ λ  = 4.42 x 105
From the ralation  λ = ∆ λ c
 ⇒ ∆ λ= λ2/c
∆ λ =4.42 x 105
λ=2.5 x 105 microns

 

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anshu said: (10:48am on Tuesday 3rd February 2015)
480 x 640 x 24 x 60 bps=442368000bps how it is 442 Mbps

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32:  

Establishing a virtual connection is virtually equivalent to

A. connecting as virtual memory
B. physically connecting a DTE and DCE
C. placing a telephone call prior to a conversion
D. placing a modem prior to a conversion
 
 

Option: C

Explanation :

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33:  

How many digits of the network user Address are known as the DNIC (Data Network Identiication Code) ?

A. First three
B. First four
C. First five
D. First seven
 
 

Option: B

Explanation :

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34:  

How many digits of the DNICC (Data Network Identiication Code) identify the country ?

A. First three
B. First four
C. First five
D. First six
 
 

Option: A

Explanation :

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35:  

Which of the following digits are known as the area code of the network user address (NUA) ?

A. 5-7
B. 1-4
C. 8-12
D. 13-14
 
 

Option: A

Explanation :

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