| A. | F1 is satisfiable, F2 is unsatisfiable |
| B. | F1 is unsatisfiable, F2 is satisfiable |
| C. | F1 is unsatisfiable, F2 is valid |
| D. | F1 & F2 are both satisfiable |
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Option: C Explanation : Click on Discuss to view users comments. |
| A. | P1 is tautology |
| B. | P1 is satisfiable |
| C. | If p is true and q is false and r is false, the P1 is true |
| D. | If p as true and q is true and r is false, then P1 is true |
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Option: C Explanation : Click on Discuss to view users comments. |
| A. | S ^ R |
| B. | S → R |
| C. | S v R |
| D. | All of above |
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Option: C Explanation : Click on Discuss to view users comments. aditya said: (3:02am on Tuesday 1st January 2013)
This is not possible.Please check again.If yes then give me solution
kriti said: (10:28pm on Sunday 19th May 2013)
make the truth table of the qiestion.then make the truth table of all the options. You will get the answer as (c).Though the calculation is a bit lengthy, but its the only way i found to calculate the answer.
NIlesh said: (2:49am on Monday 8th June 2015)
question is wrongeach part of and should be true i. e. P->R should be true when (s OR R)is truecase : when P = True and R = True and s = TrueP->R is False but (S OR R) is True.
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