A. | I,III, and II |
B. | II, I and III |
C. | III, II and I |
D. | III, I and II |
Option: D Explanation : Click on Discuss to view users comments. |
The number of canonical expressions that can be developed over a 3-valued boolean algebra is
A. | 8 |
B. | 16 |
C. | 32 |
D. | 256 |
Option: D Explanation :
Canonical form=SOP or POS Click on Discuss to view users comments. Gagan Kumar said: (11:49pm on Sunday 12th November 2017)
(X Y(1 X))(X Z)(X Y)(X Z)X=YZ
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Simplified form of the boolean expression (X + Y + XY) (X + Z) is
A. | X + Y + Z |
B. | XY + YZ |
C. | X + YZ |
D. | XZ + Y |
Option: C Explanation : Click on Discuss to view users comments. priya said: (9:40pm on Thursday 5th September 2013)
xx xy xxy xz zy zxyx xy xz zy zxyx zy zxyx zy(x 1=1)
Gagan Kumar said: (11:50pm on Sunday 12th November 2017)
(X Y(1 X))(X Z)(X Y)(X Z)(X YZ)
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Which of the following boolean expressions is not logically equivalent to all of the rest ?
A. | ab + (cd)' + cd + bd' |
B. | a (b + c) + cd |
C. | ab + ac + (cd)' |
D. | bd' + c'd' + ab + cd |
Option: A Explanation : Click on Discuss to view users comments. |
A switching function is symmetric with respect to a set of literals if and only if the function remains unchanged after
A. | Two of these literals are interchanged |
B. | Any permutation of the literals |
C. | All the literals are changed in anticlockwise order |
D. | All the literals are changed in clockwise order |
Option: B Explanation : Click on Discuss to view users comments. |
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