A decimal number has 25 digits. The number of bits needed for its equivalent binary representation is, approximately
A. | 50 |
B. | 55 |
C. | 85 |
D. | 80 |
Option: C Explanation : The largest decimal number with 25 digits is 9,999,999,999,999,999,999,999,999. The smallest decimal number in the form 2^{n}-1 which is greater than or equal to that is 19,342,813,113,834,066,795,298,815. That corresponds to 2^{84}-1. So, the minimum number of binary bits required to represent the decimal number 25 nines in a row is 84. This is 84 ones in a row. If you want to support negative as well as positive numbers, you will need 85. |
A. | 10000 |
B. | 01011 |
C. | 01100 |
D. | 01101 |
Option: B Explanation : |
The decimal number 80 can be represented in BCD code as
A. | 1000 0001 |
B. | 0101 0000 |
C. | 0010 0001 |
D. | 1000 0000 |
Option: D Explanation : |
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