Classical

Computer Organization Architecture - Cache and main memory

26:  

If each address space represents one byte of storage space, how many address lines are needed to access RAM chips arranged in a 4 x 6 array, where each chip is 8K x 4 bits

A.

13

B.

14

C.

16

D.

17

 
 

Option: D

Explanation :

As there are 4*6 = 24 chips so (as  2>= 24 ) 5 bits are required to address them.
in each RAM  number of bytes=(8k*4)/8 = 4k
So to  represent 4k we need(as 212=4096) 12 bits
Therefore  to represent total structure we need 12+5=17 bits.


27:   Four memory chips of 16 x 4 size have their address bases connected together. The system will be of size
A. 64 x 64
B. 16 x 16
C. 32 x 16
D. 256 x I
 
 

Option: B

Explanation :


28:   How many addresses are required for 25 x 40 video RAM
A. 1020
B. 1900
C. 1000
D. 2000
 
 

Option: C

Explanation :


29:   Which of the following statements is true ?
A. ROM is a Read / Write memory
B. PC points to the last instruction that was executed
C. Stack works on the principle of LIFO
D. All of above
 
 

Option: C

Explanation :




Suggest an improvement