# Computer Organization Architecture - Cache and main memory

26:

If each address space represents one byte of storage space, how many address lines are needed to access RAM chips arranged in a 4 x 6 array, where each chip is 8K x 4 bits

 A. 13 B. 14 C. 16 D. 17 Answer Report Discuss Option: D Explanation : As there are 4*6 = 24 chips so (as  25 >= 24 ) 5 bits are required to address them. in each RAM  number of bytes=(8k*4)/8 = 4k So to  represent 4k we need(as 212=4096) 12 bits Therefore  to represent total structure we need 12+5=17 bits. Click on Discuss to view users comments. Harshal Patel said: (9:02am on Tuesday 19th February 2013) how it is calculate? sonam said: (3:57am on Monday 8th April 2013) how yoy got this pleas explain Write your comments here:
27:   Four memory chips of 16 x 4 size have their address bases connected together. The system will be of size
 A. 64 x 64 B. 16 x 16 C. 32 x 16 D. 256 x I Answer Report Discuss Option: B Explanation : Click on Discuss to view users comments. Write your comments here:
28:   How many addresses are required for 25 x 40 video RAM
 A. 1020 B. 1900 C. 1000 D. 2000 Answer Report Discuss Option: C Explanation : Click on Discuss to view users comments. Write your comments here:
29:   Which of the following statements is true ?
 A. ROM is a Read / Write memory B. PC points to the last instruction that was executed C. Stack works on the principle of LIFO D. All of above Answer Report Discuss Option: C Explanation : Click on Discuss to view users comments. Write your comments here:

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