Digital Logic

The number of canonical expressions that can be developed over a 3-valued boolean algebra is

A.	8
B.	16
C.	32
D.	256
	Answer : D Explanation : Canonical form=SOP or POS No of min/MAX terms=2³=8. Therefore, Canonical form will have 28 have terms. Zero term canonical forms=⁸C₀=1. One term canonical forms=⁸C₁=8. Two term canonical forms=⁸C₂=28 Similarly total number of canonical expressions= ⁸C₀+⁸C₁+⁸C₂+⁸C₃+⁸C₄+⁸C₅+⁸C₆+⁸C₇+⁸C₈=256 Gagan Kumar said: (11:49pm on Sunday 12th November 2017) (X Y(1 X))(X Z)(X Y)(X Z)X=YZ Write your comments here: Updating your Comments.. Updating your Comments.. Report Error
	Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here.

UGC NET Paper 1 UGC NET Computer Science UGC NET Exam GATE Exam Aptitude Viva Questions General Knowledge Computer Questions Online Test

Suggest an improvement