Given the following Pascal-like program segment
Procedure A,
x, y : integer ;
Procedure B;
x, z : real ;
S1
end B;
Procedure C;
i : integer ;
S2
end C
end A;
The variables accessible in S1 and S2 are
| A. | x of A, y, x of B and z in S1 and x of B, y and i in S2 |
| B. | x of B, y and z in S1 and x of B, i and z in S2 |
| C. | x of B, z and y in S1 and x of A, i and y in S2 |
| D. | none of these |
Answer : C Explanation : vishu said: (10:32am on Tuesday 15th January 2013)
in procedure c, how come x of B can have scope?i think option c is correct.
shristi said: (11:18am on Thursday 23rd May 2013)
i think c is right
Gargi said: (12:59pm on Saturday 28th May 2016)
i also think c is correct.
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Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. |
